Question

for F = 500 lb and G = 150 lb

Solve for the force in each member, indicate whether the member is in tension or compression, and solve for the reaction forces.

ЈУ F 17 ft х 10 ft Z 12 ft

Answer 1

For equation:- solution :- Solving force in each mern bar, H02.06 Ify = 0 FBc + Pree sino cos 8 = 0 sin (42.58) C03139.9°) .:|FBE 967.62 16f Efy -0 => Foo FBECO 30 -FBE FIBO 967.62 x Cos (42.58):712.481 b E Fz=0 - FIBA & F BF singsins=o i. F13A = 96.62 x sin 142.58) gin 139.8) FISA =419.08168 Now consider point o: ł fx=0 FBp=712.4820F Fcb Cospt for loss ao FOA FOC :-612-02166 = 7612.02 x C08154.7 8) = f of coss 2 - 39.99 where , fa tan-140 12 For FOE 459.45 tbt

- from equation 9 500 -feo sing .. FCO 612.02161 from ean iso = FBct Fco cosis 502.96 FBC ebb Now consider the point o ۴۷ 22 FBC X FBA FBD FBE we ) If we observe carefully then can say 'FBE' has three component in every direct on In y direction; -FBE Coso In qodirection, FBE sinocoss In direction, of BF sino coss. where, 8 = tad-d1224102 42.58 x'= dash (oft E fy=0 => FBDT FAD cosa't feosino FAD Cosat 612.02 sim (54.78] → 412.48 FAO = 246.50 lbf
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