Question

[1+1 Write a program to solve the equation y = sqrt(5 {x}^{5) + 3 {x}^{4} + 10). a) In the function, you should take the value of the integer from the user b) The value of x should be between 1 and 9. Make sure that the user has not entered a valid value. c) Calculate the value according to the formula and print it on the screen. d) The value of the output variable y should be printed only up to two decimal places

Answer 1

• Code:-

#include<stdio.h>
#include <math.h>

int main(){
int x;
printf("Enter x value 1-9: ");
scanf("%d",&x);
if(x<1|| x>9){
printf("Invalid x value");
}
else{
float y = sqrt(pow(5*x,5)+pow(3*x,4)+10);
printf("Result x=%d and result = %.2f\n",x,y);
}
}

C equation.c X c equation.c>.... #include<stdio.h> 2. #include <math.h> 3 4 int main() { 5 int x; 6 printf("Enter x value 1.9: "); 7 scanf("%d",&x); 8 if(x<1|| x>9) { 9 printf("Invalid x value"); 10 11 else{ 12 float y = sqrt(pow ( 5*x,5)+pow ( 3*X, 4)+10); 13 printf("Result x=%d and result = %.2f\n",x,y); 14 15 16 17 سه } }

• Output:-

PROBLEMS OUTPUT DEBUG CONSOLE TERMINAL geek@geek :-/Desktop/1/july$ g++ equation.c && ./a.out Enter x value 1-9: 7 Result x=7 and result = 7260.60 geek@geek :-/Desktop/1/july$ |||

Thank You...!