Question

Write a C program to read a counter, and then, read real numbers based on the value of counter (the number must range from 0.0 to 100.0). Keep all the number entered into an array, and find the biggest, smallest and the middle number. Use void find_biggest_smallest() function to receive the array, and return biggest and smallest number. Let say biggest and smallest is 14 and 2. Therefore average = (14+2)/2 = 8.

The middle number is the number which is nearest to the average. For example, middle number is 8, the number before and after the number is 7 and 6. Since (average-6) and (7-average) yield same value, therefore, the middle number is 7 taking the nearest after the average. Use float find_middle() function to find the middle number.

Your main program should read the counter and store the number entered into an array, call the find_biggest_smallest(), find_middle() function, lastly display the biggest, smallest and middle number on the monitor.

dont have to excute just write the coding asap please need asap i only have 15 mins

Please enter number 1 (from 0 to 100) = 14.0 Please enter number 2 (from 0 to 100) 5.0 Please enter number 3 (from 0 to 100) 7.0 Please enter number 4 (from 0 to 100) 2.0 Please enter number 5 (from 0 to 100) 6.0 Please enter number 6 (from 0 to 100) 8.0 Please enter number 7 (from 0 to 100) 12.0 Please enter number 8 (from 0 to 100) 9.0 Please enter number 9 (from 0 to 100) 3.0 Please enter number 10 (from 0 to 100) 4.0 The bigest number = 14.000000 The smallest number = 2.000000 The middle number 7.000000 Process exited after 39.05 seconds with return value o Press any key to continue

Answer 1

Program:

#include <stdio.h>
#include<math.h>

//function to return the biggest and smallest number
void find_biggest_smallest(float a[], int n, float *biggest, float *smallest)
{
int i;
*biggest = *smallest = a[0];
for(i=1; i<10; i++)
{
if(a[i] > *biggest) *biggest = a[i];
if(a[i] < *smallest) *smallest = a[i];
}
}

//function to return the middle number
float find_middle(float a[], int n)
{
int i;
float sum = 0;
for(i=0; i<n; i++)
{
sum += a[i];
}
float average = sum/n;

float middle = a[0];
for(i=1; i<10; i++)
{
if(fabs(average-a[i]) < fabs(average-middle))
middle = a[i];
}
return middle;
}

//main function
int main ()
{
//variable declaration
float arr[10], biggest, smallest;
int i, n;

//prompt and read value of counter
printf("Please enter value of counter: ");
scanf("%d", &n);
//prompt and read the numbers
for(i=0; i<n; i++)
{
printf("Please enter number %d (from 0 to 100) = ", i+1);
scanf("%f",&arr[i]);
}
//find the biggest and smallest number
find_biggest_smallest(arr, n, &biggest, &smallest);
//find the middle number
float middle = find_middle(arr, n);
  
//print biggest, smallest and middle number
printf("\n\nThe biggest number = %f", biggest);
printf("\nThe smallest number = %f", smallest);
printf("\nThe middle number = %f", middle);
}

Output:

Please enter value of counter: 10
Please enter number 1 (from 0 to 100) = 14.0
Please enter number 2 (from 0 to 100) = 5.0
Please enter number 3 (from 0 to 100) = 7.0
Please enter number 4 (from 0 to 100) = 2.0
Please enter number 5 (from 0 to 100) = 6.0
Please enter number 6 (from 0 to 100) = 8.0
Please enter number 7 (from 0 to 100) = 12.0
Please enter number 8 (from 0 to 100) = 9.0
Please enter number 9 (from 0 to 100) = 3.0
Please enter number 10 (from 0 to 100) = 4.0

The biggest number = 14.000000
The smallest number = 2.000000
The middle number = 7.000000

Note Whether you face any problem or need any modification then share with me in the comment section, I'll happy to help you. Remember there are some mistakes in the question. Average calculation and middle calculation have some mistakes.