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Party Affiliation and Opinion on Tax Reform example. 83 favor indifferent opposed total democrat 138 64 285 republican 64 67
a) How many degrees of freedom are associated with this table? b) State the null hypothesis for this analysis. c) Supposed
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Answer #1

(a)

Number of rows \tiny m=2

Number of columns \tiny n=3

So, degrees of freedom \tiny v=(m-1)(n-1)=2

Hence, degrees of freedom associated with the given table is 2.

(b)

We have to test for the null hypothesis \tiny H_0:\text{Party affiliation and opinion on tax reform are independent}

against the alternative hypothesis \tiny H_1:\text{Party affiliation and opinion on tax reform are not independent}

(c)

In the actual situation we have as follows.

Observed frequencies Row total Party Democrat affiliation Republican Column total Opinion on tax Favor Indifferent Opposed 13

Expected frequencies Row total Party Democrat affiliation Republican Column total Opinion on tax Favor Indifferent Opposed 11

Chi_square Row total Party Democrat affiliation Republican Column total Opinion on tax Favor Indifferent Opposed 4.5386 0.073

\tiny \therefore \chi^2_{calculated}=\sum\frac{\left(f_o-f_e\right)^2}{f_e}=22.1525

In the moderated situation,

\tiny f^*_o=\frac{f_o}{10}

\tiny f^*_e=\frac{f_e}{10}

\tiny \therefore \chi^2_{calculated}=\sum\frac{\left(f_o^*-f_e^*\right)^2}{f_e^*}=\sum\frac{\left(f_o/10-f_e/10\right)^2}{f_e/10}=\frac{1}{10}\sum\frac{\left(f_o-f_e\right)^2}{f_e}=2.21525

Thus the value of chi square for the table is 2.21525.

(d)

Critical value is given by \tiny \chi^2_{critical}=5.99

We reject our null hypothesis if \tiny \chi^2_{calculated}>\chi^2_{critical}

Here, we observe that \tiny \chi^2_{calculated}=2.21525\ngtr5.99=\chi^2_{critical}

So, we cannot reject our null hypothesis.

Hence, based on the given data we can conclude that there is no significant evidence that party affiliation and opinion on tax reform are independent.

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