Question

Find dy/dx and the slopes of the tangent lines shown on the graph of the polar equation. (If an answer does not exist, enter DNE.) r = 2 + 3 sin() (-1,3 (2, 1) +0 2 3 dy dx = at (-1, 37) dy dx at (2,7) dy dx at (5,5) dy dx

Answer 1

polar Coordinates na 8 G810) y = rsinlo and giren 2 of 3 s1010 a= 2018) + 3 Sin10) G810) Me 2 Simlo) + 3 sin2ro) deriratino and n of are - 2 sin (D) + 3 682 (0) -3 sin2lo) an -2 sim 10+ 3 G8120) e dy 2 G810 a 6 sim Go Grus do doa 2 G810) + 3 sin (20) Sim (20) = 2 3in10)6610) Now, dy an daldo da 2 GB (0) + 3 sin (20) - 2 sin (10) + 3 668 (20) At 1,3), dr 200)+3 - 2 ()+31 ŞO

-2to At (24) do an 11 2 (0+ 3 fog -2 (0) + 3 (1) 0 +3 dy - 2 3 da 6,9 / dy ta 2 6 + 3 -2 17 +34) -5

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