1. A voltaic cell is constructed that is based on the following
reaction:
Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq).
A. If the concentration of Sn2+ in the cathode compartment is 1.30 M and the cell generates an emf of 0.25 V , what is the concentration of Pb2+ in the anode compartment?
B. If the anode compartment contains [SO2−4]= 1.30 M in equilibrium with PbSO4(s), what is the Ksp of PbSO4?
2. A voltaic cell utilizes the following reaction:
2Fe3+(aq)+H2(g)→2Fe2+(aq)+2H+(aq).
A. What is the emf for this cell when [Fe3+]= 3.60 M , PH2= 0.98 atm , [Fe2+]= 8.0×10−4 M , and the pH in both compartments is 3.85?
3.
The Nernst equation is one of the most important equations in electrochemistry. To calculate the cell potential at non-standard-state conditions, the equation is
E=E∘−2.303RTnFlog10Q
where E is the potential in volts, E∘ is the standard potential in volts, R is the gas constant, T is the temperature in kelvins, n is the number of moles of electrons transferred, F is the Faraday constant, and Q is the reaction quotient. At standard temperature, 25 ∘C or 298 K, the equation has the form
E=E∘−(0.0592n)logQ
The reaction quotient has the usual form
Q=[products]x[reactants]y
A table of standard reduction potentials gives the voltage at standard conditions, 1.00 M for all solutions and 1.00 atm for all gases. The Nernst equation allows for the calculation of the cell potential E at other conditions of concentration and pressure.
A. For the reaction
2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V
what is the cell potential at 25 ∘C if the concentrations are [Co3+]= 9.40×10−2M , [Co2+]= 0.641 M , and [Cl−]= 0.440 M and the pressure of Cl2 is PCl2= 8.60 atm ?
1. A voltaic cell is constructed that is based on the following reaction: Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq). A. If...
A voltaic cell is constructed that is based on the following reaction: Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq). a. If the concentration of Sn2+ in the cathode compartment is 1.50 M and the cell generates an emf of 0.22 V , what is the concentration of Pb2+ in the anode compartment? b. If the anode compartment contains [SO2−4]= 1.50 M in equilibrium with PbSO4(s), what is the Kspof PbSO4?
The Nernst equation is the one of the most important equations in electrochemistry. At standard temperature, 25 ∘C or 298 K, the equation has the form E=E∘−(0.0591n)logQ where E∘ is the standard reduction potential for the reaction in volts and Q is the reaction quotient. The reaction quotient has the usual form Q=[products]x[reactants]y A table of standard reduction potentials gives the voltage at standard conditions, 1.00 Mfor all solutions and 1.00 atm for all gases. The Nernst equation allows for...
Part A The Nernst equation is one of the most For the reaction 2Co3+ (aq) + 2C1_ (aq)-2Co2+ (aq) + Cl2(g). To calculate the cell potential at non- standard-state conditions, the equation is E. 0.483 v 3.80x10-2 M·Co2+-0.320 M what is the cell potential at 25°C if the concentrations are [Co3+ [CI-] = 4.00x10- M , and Ical-0.400 M? Express your answer with the appropriate units. View Avalilable Hint(s) E= Eo _ 2.sos a log10Q where E is the potential...
1. A voltaic cell is constructed based on the following redox reaction: Sn2+ (aq) + Mn (s)àSn (s) + Mn2+ (aq) Calculate Ecell at 25 oC under the following conditions: (a) Standard conditions (b) [Sn2+] = 0.0200 M; [Mn2+] = 4.00 M (c) [Sn2+] = 0.500 M; [Mn2+] = 0.00250 M 2. Consider the following redox reaction at 25oC: MnO2 (s)àMn2+ (aq) + MnO4- (aq) (a) Balance the equation in acid (b) Calculate Eocell (c) CalculateDGorxn (d) Calculate K Hint!!!...
A voltaic electrochemical cell is constructed in which the anode is a Pb2+Pb half cell and the cathode is a Cu2+, Cu+ half cell. The half-cell compartments are connected by a salt bridge. Write the anode reaction. ___+______---->_____ +______ Write the cathode reaction. ______+________---->______ +_____ Write the net cell reaction. _______+_______------>______ +_______ In the external circuit, electrons migrate_____(from or to) the Pb2+Pb electrode ______ (from or to) the Cu2+, Cu+ electrode. In the salt bridge, anions migrate______ (from or to)...
Enter electrons as e A voltaic cell is constructed in which the anode is a Mg Mg2+ half cell and the cathode is a Ni Ni2+ half cell. The half- cell compartments are connected by a salt bridge. (Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (ag) or (s). If a box is not needed, leave it blank.) The anode reaction is: The cathode reaction is: The net cell reaction is: In the external...
3) A voltaic cell employs the following redox reaction: Sn2+ (aq) + Mn (s) →Sn (s) + Mn2+ (aq) a) Make a sketch of the cell. Label the cathode, anode, Sn2+, Mn, Sn, Mn?, and salt bridge. Indicate the direction of electron flow and the direction of ion flow from the salt bridge. b) Use line notation to represent the cell. c) What is the cell potential at 25°C when [Sn?] is 0.002 M and [Mn2+] is 0.050 M?
Constants Periodic Table РапA The Nernst equation is the one of the most important equations in electrochemistry. At standard temperature, 25 °C or 298 K, the equation has the form E=E° – (0.0591 ) logQ For the reaction 2CO3+ (aq) + 2Cl(aq) +2Co2+ (aq) + C1, (g). E=0.71 V what is the cell potential at 25°C if the concentrations are Co3] =0.728 M, Co2+] = 0.143 M, and [Cl] =0.116 M and the pressure of Cl2 is Pci, = 5.60...
Conceptual: Consider a Sn(s)|Sn2+(aq) || Cu2+(aq)|Cu(s) cell. If the Sn2+ concentration is increased, what will happen to the measured Ecell value? • Calculation, full-reaction Nernst equation: Use the full Nernst equation to calculate Ecell for the conditions described… • Easier: Ni | Ni2+(0.300 M) || Cu2+(0.002 M) | Cu • Harder: Al | Al3+(0.002 M) || Cu2+(4.00 M) | Cu • Calculation, half-reaction Nernst equation: Use the Nernst equation to calculate E at pH 3.00 and [Cl- ] = 0.0035...
A voltaic cell employs the following redox reaction: Sn2+(aq)+Mn(s)---- Sn(s)+Mn2+(aq) Calculate the cell potential of 25 degrees Celsius under each of the following conditions. Part A: Sn2+= 1.15*10^-2 M; and Mn2+= 2.37 M Part B: Sn2+= 2.37 M; and Mn2+= 1.15*10^-2