Question

Chapter 02, Problem 49 Your answer is partially corect. Try again A hot-ar ballaon is rising upward with a constant speed of 3.81 m/s. When the balloon is 4.17 m above the ground, the baloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground? Number o.92 Units the tolerance is +/-2%-

Answer 1

Ans: Given riven Velocity of ballon= 3.81 mis height of ballona 4.17 m acceleration dele to gravity (9)=9.8 When the compass ind droped It will have same velocity granity in opposite direction. from ballon as ballon but Now We have we areas 820 4= 3.81 ang= -9.8 . S u = (3181) 2 ₃ 0.74 m 219.89 means Compon reached at a top of (4.17 + 0.74) 24.91 m it Now V= utat N20 at the top to-4-4 (2--9) - 3-87 that means Now at Ziso, and 9.8 ~ 0.39 Compass reeach at top in 0.395. 4.91m velocity of compass is it attain Condition of free fall under

again to atras = ✓ 2gs Casu=0, a24g in 2nd case) ✓ 2x Gr8 x 4.91 9.81 Now so uttt att uzo Sa - 6029) I att ta Ves V CV 219091 204.91 Hence total time pass (+0.39 ) 21.39 s.