A hot-air balloon is rising upward with a constant speed of 2.15 m/s. When the balloon is 2.31 m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground?
Using 2nd equation of motion,
-y = ut - 0.5gt^w
-2.31 = (2.15 t) - (0.5 x 9.8 x t^2)
4.9t^2 - 2.15t - 2.31 = 0
Time, t = 0.94 sec
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