Question

Workshop 1 Solutions Hydrochloric acid is usually purchased of 1.20 g/mL. with water? in a concentrated form that is 37.0% HCl by mass and has a density How much concentrated solution would you take to prepare 2.75L of 0.575M HCI by mixing 1. 6.965

Answer 1

According to law of dilution   MV = M'V'

Where

M = Molarity of stock = (10 x percent of purity x density)/molar mass of HCl

   = ( 10 x 37.0 x 1.20g/mL ) / 36.5 (g/mole)

   = 12.16 M

V = Volume of the stock = ?

M' = Molarity of dilute solution = 0.575 M

V' = Volume of the dilute solution = 2.75 L

Plug the values we get, V = (M'V')/M

                                     = ( 0.575 x 2.75) / 12.16

                                     = 0.130 L

                                     = 130mL

So take 130 mL of concentrated solution and make upto 2.75 L with water we get required solution