Question

5. You have a 5.0 M solution of phosphoric acid, H3PO4 a. Write an equation three dissociation equations. b. As the species becomes more negative, the protons are more attracted to the species. What does this do to acid strength? C. Determine the concentration of all species in solution. Below are the needed ka values. • Ka, = 7.5 x 10-3 • Ka, = 6.2 x 10-8 • Ka, = 4.8 x 10-13 I MacBook 3013

Answer 1

а The three one kai equations H₃ Pog H, Pou H-T-- H, PO4 kang H-PHPo -- Са? HPo2 - HT POUR «а As the species become mone negative the protons are strongly attracted to the pou (Phosphate ion) hence Acid strength reduces becomes more negative as the species ☺ the solution thaos Tire], Fix pou), H3P04], 7H40,41] Проч) kas Но Роч -5°юм [н] (H, Pби 1 TH₂ Pou] it and he H₂pou are е алмай, медиа от, 2-5Х10 х 50 [1] ох, үн'] = 0-14 34Н. ЭГН; РО) kas = TH*][HP0:32] 2. little tt TH, Po11 о", с 2х10-8 = Ютуб: 14364 0 1430 аѕ еx). HPO42 |-04 X10 чM from and dissociation

- kaz Гигром) | POu? ) 4-8х10 - 13 — дея х2 Г-04x\о-ч - 2:25x50 м Jнт]> 0 14 24 м врод)= 4306ч н ) и роҳ ]= 6-1436M Гиро-2 = 1:04x10 м Грои? - 1 = 9-25ків м.