The location of the equivalent concentrated force to the triangular distributed load shown, measured from the...
4. (12 points) Replace the distributed load on the beam with a statically equivalent concentrated force and determine the location of that force with respect to point B. T equation of the parabola is wx)-37.5x2+800, where the origin is at point B. he Vertex Parabola 800 N/m 200 N/m 4. (12 points) Replace the distributed load on the beam with a statically equivalent concentrated force and determine the location of that force with respect to point B. T equation of...
For the distributed load shown below, determine the equivalent force's magnitude and location, measured from point O. Let a = 1.41 kN/m3,6 = 3.80 kN/m² , and L = 2.70 m.
In the figure, there are distributed load of triangular and rectangular shape. F1= 2 and F2 = 7 are the forces in the distributed load as shown. M= 14 is the moment applied at the right end at point E. The distances between every points are given, where the distance between B and C is b= 3. All the distances are in m. Forces are in N. What will be the magnitude of the support reaction force at A? Round...
Replace the loading on the beam by an equivalent resultant force and specify its location measured from point A. (b) Calculate the value of the reactions at support A and support B. (c) calculate the shear, normal force, and bending moment at a point 1.5 m to the right of A. (d) Same as (c) but at a point 0.5 m to the right of B. The system is in equilibrium.
Replace the distributed loading with an equivalent resultant force, and specify its location on the beam measured from point A.
Problem 2 Consider a simply supported symmetric I beam ABCD carrying a uniformly distributed load w and a concentrated load F as shown in Figure 2. Young's modulus of the beam is 200 GPa. F 8 kN 8cm 3cm 3cm 7 m 5 m 3 m 2cm W= 6 kN/m 6cm A D B 2cm 7TITT TITIT Figure 2 1) Replace the support C with the reaction force Rc, and using static equilibrium find the reactions at point A and...
With a U cross section, is subjected to uniformly distributed force 11 kN/m and a concentrated load of 12 kN as shown. (a) the reaction at supports A and B, (b) sketch the shear diagram and the moment diagram, (c) determine the location of neutral axis of the cross section and calculate its area moment of inertia about the neutral axis, and (d) determine absolute maximum bending stress and (e) absolute maximum transverse shear stress.
Problem 2 Consider a simply supported symmetric I beam ABCD carrying a uniformly distributed load w and a concentrated load F as shown in Figure 2. Young's modulus of the beam is 200 GPa F- 8 kNN 8cm 3cm 3cm w- 6 kN/m 6cm 2cm Figure 2 1) Replace the support C with the reaction force Rc, and using static equilibrium find the reactions at point A and B in terms of Ro 2) Using the boundary conditions, calculate the...
Problem #4: The frame supports the triangular distributed load shown Use Mohr's circle to determine the normal and shear stresses at point E that act perpendicular and parallel, respectively, to the grains. The grains at this point make an angle of 45° with the horizontal as shown. Point C is the pin support. 900 N/m 35 75 mmi 200 mm 2.4 m 0.6 m 100 mm 3 m 45° 50 mm 30 mm 1.5 m 100 mm Problem #4: The...
P=10 kN A cantilever beam is subiected to a concentrated force P, a uniformly distributed load w and a moment MI shown in the figure. Neglect the weight of the beam. (a) Draw the free body diagram for the beam showing all the 2 m reactions, replacing the support M.-2 kNm by the reaction forces/moments. (b) Use the equations of equilibrium to find the reaction forces/moments at R (c) Give the expression for the shear force, V- V(x), and the...