Question

Match the definition with the term ____ Transition from solid to liquid A. condensation ____ Transition from liquid to gas B. Boiling ____ Transition from solid to gas C. Freezing _____ Transition from gas to liquid D. Melting _____ Transition from liquid to solid E. Sublimation How many milligrams are in 8.22 moles of sodium hydroxide (molar mass = 39.997 g/mol). Be sure to show your work, correctly label your units and use the correct number of significant figures. A solution is prepared by dissolving 8.50 g of sodium bromide in 225.1 mL of water. is the molarity of the solution? Show all of your work, (be sure to include units and the number of significant figures) Balance the below equations Fe_2 O_3 C rightarrow Fe+ CO_2 C_5 H_10 O + O_2 rightarrow CO_2 + H_2 O AlCl_3 H_2 O rightarrow Al(OH)_3 + HCl Al + Ag_2S rightarrow Ag + Al_2 S_3

Answer 1

Transition from solid to liquid Melting Transition from liquid to gas Boiling Transition from solid to gas Sublimation Transition from gas to liquid condensation Transition from liquid to solid Freezing No. of moles = Weight of sample/Molar mass of the sample Given no. of moles = 8.22 Molar mass of the sample = 39.997 g/mole implies 8.22mle = Weight of sample/39.997 g/ implies Weight of the sample = 328.72534 g implies Weight of NaOH = 328775.34mg Molarity = Weight of sample(in 'g')/Molecular Weight of sample times 1000/Volume (in ml) Molecular height of sodium Bromide = 102.894g/mol Given. Weight of the sample = 8.5g volume = 225.1ml implies Molarity = 8.5/102.894 times 1000/225.1 Molarity of the solution = 0.36698M \r\n Fe_2O_3 + C rightarrow Fe + CO_2 a) Balance 'Fe' on Both sides Fe_2O_3 + C rightarrow 2Fe + Co_2 (2) Balance 'O' on Both sides Fe_2O_3 + C rightarrow 2FFe + 3/2 CO_2 (3) Balance 'C' on Both sides. Fe_2O_3 + 3/2 C rightarrow 2Fe + 3/2 CO_2