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Use the following data to sketch a cooling curve and calculate the amount of heat lost for 1.5 moles of trihexalon, a biologi i need help figuring out this problem . please!
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110°C 93°C 21 °C 16°C Temperature Time

There are total five steps in this cooling process Step -1 vapor trihexalon from 110 °C to vapor trihexalon at 93°C q, rmoles

Step-4 liquid trihexalon from 21°C to solid trihexalon at 21°C 94 =AH fus X moles of trihexalon =(11.7 kJ /mol)(1.5 mol) = 15

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