Question

(4 points) In 2003, the price of a certain automobile was approximately $30,500.00 with a depreciation of $2,010.00 per year. After how many years will the car's value be $16,430.00? a) Write an equation to answer the question. Let t represent the number of years after 2003. Do not use commas in your numbers. The equation will only contain one variable. Answer: b) Solve the equation to answer the question above. (Note: Include the units, in this case years. Do not include commas in your answer.) Answer:

Answer 1

solution: given data is

in 2003, price of automobile = $30500

depreviation = $2010 per year

now, let price of automobile is denoted by P

and depreviation means , the price of automibline decreases by $2010 in t year

so, the we get the equation as

=> P = 30500 - 2010t

B) given value of P is P = $16430, we have to find t at p= 16430

now putting p= 16430 in above equation we get

=> 16430 = 30500 - 2010t

=> 2010t = 30500 - 16430

=> 2010t = 14070

=> t = 7 year

so, after 7 year the car's value will be $16430.