solution
At 91.9% confidence level the z is ,
= 1 - 91.9% = 1 - 0.919= 0.081
/ 2 = 0.0405
Z / 2 = Z0.0405 = 1.745 ( Using z table )
You intend to estimate a population proportion with a confidence interval. The data suggests that the...
You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a reasonable approximation for the binomial distribution in this case. While it is an uncommon confidence level, find the critical value that corresponds to a confidence level of 81.2%. (Report answer accurate to three decimal places with appropriate rounding.) za/2 = ±
You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a reasonable approximation for the binomial distribution in this case. Find the critical value that corresponds to a confidence level of 99%. (Report answer accurate to three decimal places with appropriate rounding) Za/2
Yifei Xie s Calendar Gradebook Sp18> Assessment work Due Thu 05/31/2018 11:59 pm You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a reasonable approximation for the binomial distribution in this case. while it is an uncommon confidence level, find the critical value that corresponds to a confidence level of97.5%. (Report answer accurate to three decimal places with appropriate rounding.) Points possible: 1 This is attempt 1 of 4. Submit
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need answer as fast as possible please Show Intro/Instruct You intend to estimate a popullon mean with a confidence interval You believe the population to have a normal distribution. Your sample size is 65. Find the critical value that corresponds to a confidence level of 98%. (Report answer accurate to three decimal places with appropriate rounding.) Kova = + Lic Points possible: 0 This is attempt 1 of 3.
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