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Problem 6 (1 pt Use the IHNMR and 13C NMR spectra

Please explain why is it Cis or trans. How can we differentiate the isomers? Why one shift futhur downfield than the other?

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Answer #1

The spectrum here for compound clearly indicates it is of trans 1,2-dichloroethene.

The free rotation of atoms in the alkenes are restricted so in H-NMR of the trans-1,2-dichloroethene the hydrogens in different chemical environment and there are two hydrogen atoms so they couple with each other and each peak splits in to two. While for cis-isomer we will get a single peak at around 6.3 ppm.

In C13 NMR of the trans-1,2-dichloroethene there are two peaks in the spectrum indicating two carbons in different chemical environment. But in case of cis-isomer it will have only one peak showing both the carbons are in similar environment and we will have peak at arround 120 ppm.

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