Question

I need help with this physics problem.

The Large Hadron Collider (LHC) is designed to accelerate protons around a ring 27 km in circumference using over 1,600 magnets that produce an 8.3 T field. The mass spectrometer equation cannot be used for this calculation since the protons are highly relativistic (v c). The kinetic energy becomes Ek = pc where p is the momentum, still given by p=qBr. Determine the proton's kinetic energy (in Joules) and convert to units of Tera electron-volts (TeV). 1eV=1.6 x 10-19 Joules and Tera = 1012, so 1 TeV = 1.6 x 10-7 Joules. Your answer should be near 10 TeV. The proton's mass is 1.67 x 10-27 kg, almost 2000 times the electron’s mass.

Answer 1

Ans) circumference - t 27 km = 27 x 10 m hence the radim - 1 = = 1 = 1/2 B 8.31 q= = 1.68 1019 a change on proton p=q B1 = pe Ex = a Bac XIX.108 T Kinetic energy I EK LC 1 6 x 109 x 8.5 XI 2K = 1.6X8.3x27x? x 108 J an = 171.19979 X108 g =171.19979 x 108 x 1 Tev 1.6X1OF E 106.999 x 1011 Tev 10.699 Tevi so psoton's kinetic energy = 10.699 Tev