Question

A department store decides to examine the proportion of shoppers who would use a cafeteria in the store. Of the 250 shoppers surveyed at random, 175 said that they would use a cafeteria..
A 90% confidence interval estimate for the proportion of shoppers who would use a cafeteria is:

Answer 1

from the above given information 1 - 250 a Ñ = 196 = 0.7 = 175 then 90% (-I for proportion is giom by ß & Za BCAA) then + 8 2011 then critical value at * 0.1 is given by (Calculated from Standard Normal table) 2 o ) = 1.645 o - Î + 1695 x 10.7x0.3 0.780.3 0.7 t 1 645 x 0.21 0.21 250 V 250 - 0.7 ± 0.0476 0.7 0.048 - option (() is correct .