Question

7. Give the formula of avoiding roundoff error to solve each of the fol- lowing problem and compute the numerical values. All(3). 0.02 - e-0.02 0.03 = 0, e* = 1+2 + + (Hint: use the Taylor series of et about x = 1 + ..., take x = 0.02, 0.03 = 3c/2) 6

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Answer #1

#first one source code:

a=1/3;
b=-123/4;
c=1/6;
x1=(-b+sqrt(b^2-4*a*c))/(2*a);
x2=(c/a)/(x1);
fprintf("x1=%.4f\nx2=%.4f\n",x1,x2);

#outtput:

>> data xl=92.2446 X2=0.0054 >>|

#second one source code:

data=log(50-sqrt(2499));
printf("%.4f\n",data);

#output:

Command Window >> data -4.6051 >> |

#third one source code in matlab:

data=(exp(0.02)-exp(-0.02))/(0.03);
fprintf("%.4f\n",data);

#output:

>> data 1.3334 >> |

#forth one source code;

data=sqrt(100.01)-sqrt(99.99);
fprintf("%.4f\n",data);

#output:

Command Window >> data 0.0010 >> |

#by using matlab we can get the data all are 4 decimal places..

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