now we find the coefficient of the friction at package A
a=g(sin(theta)-cos(theta))
3=9.8(sin30-cos30)
0.31=0.5-0.87
0.87=0.2
coefficient of the friction =0.23
now we find the acceleration of the package B
acceleration a2=9.8(sin15-0.23*cos15)
=0.36 m/s^2
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