there is a 6kg wooden block with a positive velocity and an acceleration of -6.0 m/s^2...

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there is a 6kg wooden block with a positive velocity and an acceleration of -6.0 m/s^2...

there is a 6kg wooden block with a positive velocity and an acceleration of -6.0 m/s^2 sliding across a table. Calculate the coefficient of kinetic friction.

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Answer 1

Answer #1

The relation between friction force and normal force is

fk = uk N

ma = uk N

ma = uk mg

a = uk g

uk = 6 m/s^2/9.8 m/s^2

=0.61

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Answer 2

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there is a 6kg wooden block with a positive velocity and an acceleration of -6.0 m/s^2...

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there is a 6kg wooden block with a positive velocity and an acceleration of -6.0 m/s^2...

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