Question

A genetic experiment with peas resulted in one sample of offspring that consisted of 421 green peas and 158 yellow peas. 

a. Construct a 90% confidence interval to estimate of the percentage of yellow peas 

b. It was expected that 25% of the offspring peas would be yelow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? 

Answer 1

x=158

n=421+158=579

p^=x/n

p=158/579=0.273

#90 % CI for proportion is

a) Now to find confidence interval for proportion of yellow peas, the formula is

p) – ze* \/f*(1 – h) (0.273–1.64*1 0.273 + (1 -0.273) 579 0 0 Add a comment

For 90% confidence level , zc = 1.645

(0.273–1.64*1 0.273 + (1 -0.273) 579

(0.242

#90% confidence interval 0.242

Ansb:

No ,the confidence interval includes so true percentage could easily equal 25%

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