Question

2 AT TIME to THE VOLTAGE Across THE CAPACITOR IS lov. IF THE SWITCH IS CLOSED AT THIS TIME Fo% a) MAX ENERGY STORED BY Cup. b) MAX ENERGY STORED BY INDUCTOR, K c) "TIMO AFTER SWITCH IS CLOSED WHEN INDULTOR STOROS MAX. ENERGY. * LEIRST TIME) d) Max CURRENT IN CIRCUITO 1. e) FIRST TIME THIS CURRENT occURES. c=20mF L=5H leu

Answer 1

I elle w= JSx20x150 c=20MF C = 20x10 of a L=5H Charge on capacitor at time it is q=2 sincetto) where VLC rad's 5x20x10-6 - Tw=108rad's & is initial phase and. Wo is maseinum charge. maximum voltage across capacitor is lov Qo = 2011 oxio Coralomb. Qo= 2 x10-4 corelomb Maximum energy stored in capacitor is vo= J 2 x 20x106 (2x10432 U=1035 b Net energy to oscillate between capacitor and inductor. When inductor stores maximum energy then energy stored in capacitor es zero.

2 Maximum energy stored by inductor is 10o=103] q= senceett +0) At t=0,9 = Qo ..%= to sin (0+6) sind=10=1 :9= Q sinfest +92) 9 = Qocos (cat) .: Current through the circuit is d coscut Qolo (sin cest) dt I= -lo sinuat) where, to=Qw is amplitude of current. Masee mem energy stored in the inductor when magnitude of current is maseimum For first time, sincet=I » celt=5 I= do dt 2 = see ก 2X 100 > t = h w » It=1.5708x10 2 sec

@ maximum current is Io= low fo=2x104x100 A Io = 0.02A 2 2 121=fo Ro=1 to senot 1=1 sinuet! for 1st time sinullal, alt=h = kon » t= 1.5708X102 sec is t=n 2 w sec