Question

What is the voltage across the capacitor immediately after the switch S is closed? At that instant,

what current flows out of the battery?

100 10.02 12.0 V' C= 1.5uF ২9.02 5.0 )

Answer 1

12 Zion VV 12 v 1 А — — B C=1.5MF 51 when switch is closed at t=0 Capacitor allow all the coment to flow through it, thus capacitor will be will be short Circuited. And t= 0 Capacitor block all the Corrent through it, thus becoming open circuiti . This is called Steady state. This there in this case: thosted 12N & Spoivant circuit: 12V I S $181 Ri II R₂ & RB 11 RG

Bor Inese Garden om 12V A Further Simplifying the circuit ! we have nere RA= R1 R2 - Re R2 Rit Rr. an RR. Rg 11 R & R B = Rp 11R2 – Rz. Rz is RA A 1 x 10 = 100.91 107) TT & RR - - 9x5 – 45 - 3.21 the +5 - 16 , Above Given crmit corrent is given by : E is here - Retre 0.91+8121 MY Rat R2. In 14- 2.912 Amph. Am ger
at t=0 capacitor allows all the current to flow trough it thus acting as a short circuited wire.