Solution :
Given that ,
mean =
= 460
standard deviation =
= 80
P(x
400) = 1 - P(x
400)
= 1 - P[(x -
) /
(400 - 460) / 80]
= 1 - P(z
-0.75)
= 1 - 0.2266
= 0.7734
Answer = 0.7734
A large number of applicants for admission to graduate study in business are given an aptitude...
A large number of applicants for admission to graduate study in business are given an aptitude test. Scores are normally distributed with a mean of 460 and standard deviation of 80. What fraction of the applicants would you expect to have a score of 400 or above? If the random variable Z has a standard normal distribution, then PIZ's -1.37) is:
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