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Suppose babies born in a large hospital have a mean weight of 3242 grams, and a standard deviation of 446 grams. if 107 babie
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Answer #1

We have mean = 3242, standard deviation (sd) = 446 and sample size n = 107

To find P(X < 3285)

= P(z<\frac{x-\mu}{\sigma/\sqrt{n}}) \\ \ \\ = P(z<\frac{3285-3242}{446/\sqrt{107}}) \\ \ \\ = P(z<\frac{43}{43.11644}) \\ \ \\ = P(z<0.9973 ) \\ \ \\ = 0.8407(using z distribution table)

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