Buffer Solution is a water solvent based solution which consists of a mixture containing a weak acid and the conjugate base of the weak acid, or a weak base and the conjugate acid of the weak base. They resist a change in pH upon dilution or upon the addition of small amounts of acid/alkali to them
so Here weak base is KNO3 and and its conjugate acid is HNO3
So Ans A as it has equal volume
A buffer can be formed from the combination of A) 50.0 mL of 0.50 M HNO3...
We have (a) 50.0 mL of 0.10 M NH3 solution, (b) 50.0 mL of 0.12 M HNO3 solution, (c) 50.0 mL of 0.12 M NaOH solution, and (d) 50.0 mL of 0.06 M HClO4 solution. Can you make a buffer by combining two of these solutions? If so, which ones? What would be the pH of the buffer solution? Please explain
1. Consider the titration of 50.0 mL of 0.200 M HNO3 with 0.100 M NaOH solution. What volume of NaOH is required to reach the equivalence point in the titration? a. 25.0 mL b. 50.0 mL c. 1.00 × 10^2 mL d. 1.50 × 10^2 mL 2. Consider the following acid–base titrations: I) 50 mL of 0.1 M HCl is titrated with 0.2 M KOH. II) 50 mL of 0.1 M CH3COOH is titrated with 0.2 M KOH. Which statement...
Would the following solutions provide an effective buffer. a) 250. mL of 0.15 M HC2H3O2 + 25 mL of 0.10 M NaOH yes no b) 125 mL of 0.50 M HNO2 + 75 mL of 0.40 M KNO2 yes no c) 250. mL of 0.25 M HCO2H + 125 mL of 0.50 M KOH yes no d) 250. mL of 0.50 M HClO4 + 150. mL of 0.50 M NaClO4 yes no e) 250. mL of 0.50 NaOH + 500....
4. (12 pts) A buffer is created by mixing 50.0 mL of 0.50 M C6H5N and 40.0 mL of 1.0M HC.HSNCI. What is the final pH of the solution if 20.0 mL of 0.50 M KOH is added to the buffer at 25 °C? K(C6H5N) - 1.4 x 10-9 To receive full credit, all work must be explicitly shown, including the relevant neutralization and hydrolysis chemical reactions that are occurring, and do not use the Henderson-Hasselbalch equation.
A: 48.0 mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 24.0 mL of KOH at 25 ∘C B: Consider the titration of 50.0 mL of 0.20 M NH3 (Kb=1.8×10−5) with 0.20 M HNO3. Calculate the pH after addition of 50.0 mL of the titrant at 25 ∘C. C: A 30.0-mL volume of 0.50 M CH3COOH (Ka=1.8×10−5) was titrated with 0.50 M NaOH. Calculate the pH after addition of 30.0 mL of NaOH at 25...
Part B A 72.0 mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 36.0 mL of KOH at 25 ∘C. Express the pH numerically. Part C Consider the titration of 50.0 mL of 0.20 M NH3 (Kb=1.8×10−5) with 0.20 M HNO3. Calculate the pH after addition of 50.0 mL of the titrant at 25 ∘C. Express the pH numerically. Part D A 30.0-mL volume of 0.50 M CH3COOH (Ka=1.8×10−5) was titrated with 0.50 M NaOH. Calculate the...
Part B A 96.0 mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 48.0 mL of KOH at 25 ∘C. Express the pH numerically. Part C Consider the titration of 50.0 mL of 0.20 M NH3 (Kb=1.8×10−5) with 0.20 M HNO3. Calculate the pH after addition of 50.0 mL of the titrant at 25 ∘C. Express the pH numerically. Part D A 30.0-mL volume of 0.50 M CH3COOH (Ka=1.8×10−5) was titrated with 0.50 M NaOH. Calculate...
6.)Part B A 64.0 mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 32.0 mL of KOH. Express the pH numerically. 7.) Part C Consider the titration of 50.0 mL of 0.20 M NH3 (Kb=1.8×10−5) with 0.20 M HNO3. Calculate the pH after addition of 50.0 mL of the titrant. Express the pH numerically. 8.) Part D A 30.0-mL volume of 0.50 M CH3COOH (Ka=1.8×10−5) was titrated with 0.50 M NaOH....
What volume of 0.50 M HNO3 solution is required to react completely with 40.0 mL of 0.20 M Ba(OH)2? Ba(OH)2 + 2 HNO3 Ba(NO3)2 + 2 H2O A) 16 mL B) 32 mL C) 64 mL D) 8 mL E) 4 mL
31. To what volume should you dilute 50.0 mL of a 12 M stock HNO3 solution to obtain a 0.100 M HNO3 solution? MISSED THIS? Read Section 5.2; Watch KCV 5.2, IWE 5.3 react WILII 129 TIL U10.100 J D 35. What is the minimum amount of 6.0 M H2SO4 necessary to produce 25.0 g of Hz(8) according to the reaction between aluminum and sulfuric acid? MISSED THIS? Read Section 5.3; Watch IWE 5.4 2 Al(s) + 3 H2SO4(aq) -...