use:
pH = -log [H+]
11.63 = -log [H+]
[H+] = 2.344*10^-12 M
use:
[OH-] = Kw/[H+]
Kw is dissociation constant of water whose value is 1.0*10^-14 at
25 oC
[OH-] = (1.0*10^-14)/[H+]
[OH-] = (1.0*10^-14)/(2.344*10^-12)
[OH-] = 4.266*10^-3 M
[NaOH] = [OH-]
= 4.266*10^-3 M
Answer: 4.266*10^-3 M
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