Question

8.2.19-T The table below contains the overall miles per gallon (MPG) of a type of vehicle Complete parts a and b below 24 24 20 26 24 29 35 23 28 20 44 31 25 22 a. Construct a 95% confidence interval estimate for the population mean MPG for this type of vehicle, assuming a normal distribution The 95% confidence interval estimate is from (Round to one decimal place as needed) MPG to MPG 8.EOC.57-E Question Help A consulting firm wants to study communication deficiencies in the health care industry. A random sample of 79 health care clinicians reveals the following Time wasted in a day due to outdated communication technologies: X - 43 minutes, 5-10 minutes. Fifty-nine health care clinicians cite inefficiency of pagers as the reason for the wasted time. Complete parts (a) and (b) below a. Construct a 95% confidence interval estimate for the population mean time wasted in a day due to outdated communication technologies (Round to two decimal places as needed.) 8.EOC.65-E Question Help A quality characteristic of interest for a tea-bag-filling process is the weight of the tea in the individual bags. The label weight on the package indicates that the mean amount is 5.56 grams of tea in a bag. Problems arise if the bags are underfilled or if the mean amount of tea in a bag exceeds the label weight. The accompanying data are the weights, in grams, of a sample of 50 tea bags produced in one hour by a single machine. Complete parts (a) through (c) below. Click the icon to view the tea bag weight data. B Click the icon to view the tea bag weight data. ДА в со 1 Tea Bags 2 5.31 5.53 5.62 5.35 5.51 5.39 5.38 5.52 5.41 5.54 5.42 5.53 5.47 5.57 5.57 5.47 5.57 5.49 5.48 5.59 5.5 5.59 45.495.61 5.495.59 5.5 5.61 a. Construct a 95% confidence interval estimate for the population mean weight of the tea bags. 5.47 (Round to two decimal places as needed) 5.58 567 5.69

Answer 1

8.2.19)

sample mean         x=	27.500
sample size             n=	14.00
sample std deviation s=	7.450
std error sx=s/√n=	1.9911

for 95% CI; and 13 df, critical t=		2.1600
margin of error E=t*std error                            =		4.301
lower bound=sample mean-E =		23.199
Upper bound=sample mean+E=		31.801
from above 95% confidence interval for population mean =(23.2,31.8)

8.EOC.57_E)

sample mean 'x̄=	43.000
sample size   n=	79.00
sample std deviation s=	10.000
std error 'sx=s/√n=	1.1251

for 95% CI; and 78 df, value of t=		1.9910
margin of error E=t*std error    =		2.2401
lower bound=sample mean-E =		40.76
Upper bound=sample mean+E =		45.24
from above 95% confidence interval for population mean =(40.76,45.24)