Question

At time t = 0, a 4.0 kg particle with velocity v =

0 0
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Answer #1

m = 0.4 Kg
v =

(a)
Angular Momentum,
L = r x p
L = (6.0i^ + 5.0j^) x 4.0 * (5.0 i^ - 6.0 j^)
L = -61 k^ * 4 Kgm^2/s
L = - 244 k^ Kgm^2/s

(b)
τ = r x F
τ =  (6.0i^ + 5.0j^) x (-2.0 i^)
τ = 10 k^ Nm

(c)
Rate of change of angular momentum = net torque acting on the body
dL/dt = τ = 10 k^ Kg m^2/s^2

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