Homework Answers
public int mystery(int number){
if(number == 0)
return 1;
else
return 1*mystery(number-1);
}
So, lets there is a call: mystery(10)
so, output: 1*mystery(9)
1*1*mystery(8)
------------
----------
1*1*1*....10
times
So, output = 1, for any value of number > 0
Answer: d. None of the above
Add Answer to:
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C++
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3. Consider the mystery method given. public static int mystery ( int n) [ if (n == 0 ) { return 1; How do we get the values for recurse? else if (n%2 == 0 ) { int recurse = mystery ( n - 1); int result = recurse + n; return result; since n =5, we go to the else statement and do int recurse = mystery(5-1) which equals 4? why is 3 written? else { int recurse =...
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C++
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