The code for a recursive function 'mystery' appears below. Assume we passed the following array as...
The code for a recursive function 'mystery' appears below.
Assume we passed the following array as x[]:
int x[] = { 10, 20, 25, 25 };
How would we call mystery() so the return value is 1?
int mystery(const int x[], int n, int mysteryValue)
{
int count = 0;
if (n <= 0)
return 0;
else
{
if (x[n - 1] == mysteryValue)
count = 1;
return mystery(x, n - 1, mysteryValue) + count;
}
}
1mystery(x, 4, 0)
2mystery(x, 4, 25)
3mystery(x, 4, 1)
4mystery(x, 4, 20)
Homework Answers
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OPTION D IS CORRECT
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The code for a recursive function 'mystery' appears below.
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