Question

C++ Programming

Write a function that takes an integer array, the array size and a number. And it determines how many times that number appears in the array. Just copy the following code and paste it to your answer. And fill the corresponding part. 

#include < iostream >

using namespace atd; 

int howmany (int array lint , int number){

 //Your code comes here

}

 int main() {

const int N =10; 

int array[N] = [11,3,2,1,3,4,6,9,1.3); 

int count = howlany(array,N,3);

cout << 3 < "appesa" << cout << "times!";

 return 0;

Answer 1

Here is the required code for your problem

{ 1 #include 2 using namespace std; 3 int howmany(int array[], int n, int number) 4-{ int count=0; for(int i=0;i

here is the code

#include
using namespace std;
int howmany(int array[],int n,int number)
{
int count=0;
for(int i=0;i {
//check equality and increase the counter
if (array[i]==number)
count=count+1;
}
//return count
return count;
}
int main()
{ const int n=10;
int array[n]={1,3,2,4,3,4,6,9,1,3};
int count=howmany(array,n,3);
cout<<3<<" appears "< return 0;
}

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Answer 2

#include  
using namespace std; 
int howmany(int array[],int n,int number) 
{
 int count=0; 
 for(int i=0;i