a) 1/i = 1/f - 1/p = 1/20 - 1/10
i = - 20 cm
m = -i / p = - ( - 20) / p = 20 / 10 = 2
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b) m = -i/p
i = m*p = 10*1 = - 10
i = -10 cm
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c) 1/i = 1/20 - 1/30
i = 60 cm
m = - 60 / 30 =
m = -2
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d) r = 40 cm , so f = 40/2 = 20 cm
1/i = 1/20 - 1/60
i = 30 cm
m = -30 / 60
m = -0.5
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e) 1/p = 1/f - 1/i
1/p = -1/20 - (-1/10)
p = 20 cm
m = - (-10) / 20
m = 0.5
___________________________________________________________________________________________
Please answer the blanks HRW6 35-10P Fill in Table 35-3, each row of which refers to...
More mirrors. Object O stands on the central axis of a spherical or plane mirror. For this situation (see the table below, all distances are in centimeters) , find (a) the type of mirror (concave or convex), (b) the focal distancef, (c) the radius of curvature of the mirror (including sign), (d) image distance (including sign), whether (e) the image is real or virtual, (f) inverted (I) or noninverted (NI) from O, and (g) on the same side of the...
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webassign.net Active Figure 26.25 Thin Lenses The animation below shows a thin lens, an object (blue arrow) and an image (tan arrow). Three rays are shown that locate the positic orientation, and size of the image. Readouts are provided for object distance, object height, image distance and image height. Instructions: Click and drag the blue object. Click the button in the lower left of the applet window to toggle between a conc convex lens. Explore Images formed by thin lenses...
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