Question

8.7 Draw the displacement schedule for a follower that rises through a total displacement of 3 in with cycloidal motion in 120° of cam rotation. The follower then dwells for 90° and returns to 0° with simple harmonic motion in 90° of cam rota- tion. The follower then dwells for 60° before repeating the cycle.

Answer 1

"The profile equation are for 0 lessthanorequalto theta lessthanorequalto 2 pi/3 beta = 2 pi/3 and y_1 = l(theta/beta - 1/2 pi sin 2 pi theta/beta) = 3 (3 theta/2 pi -1/2 pi sin 3 theta) y_16' = l(1/beta - 1/beta cos 2 pi theta/beta) = 3(3/2 pi - 3/2 pi cos 3 theta) y_1^"" = L(2 pi/beta^2 sin 2 pi theta/beta) = 3(9/2 pi sin 3 theta) for 2 pi/3 lessthanorequalto theta lessthanorequalto 9 pi/6 y_2 = 6 for the reaction 7 pi/6 lessthanorequalto theta lessthanorequalto 5 pi/3 beta = pi/2 and y_3 = l/2 (1 + cos pi theta/beta) = 1.5 (1 + cos 2 theta) for the remainder of the cycle 5 pi/3 lessthanorequalto theta lessthanorequalto 2 pi and y_4 = 0 the displacement diagram is given below \r\n postion (2) velocity (3) Acceleration"