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A flask contains 1.00 L of a pure gas at 0.850 atm and 20.0°C. The mass of the gas is 1.13 g. a) What is the molar mass of th
arades eople A mixture of gases containing 21.0 g of N2, 106.5 g of Cly, and 120 g of He at 14 °C is in a 50.0L container. Wh
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Answer #1

ANSWERS-

  • 1st image- 32 g/mole, Oxygen
  • 2nd image- 2.827 atm

1st image solution-

V = 1.00 L

P = 0.850 atm

T= 20.0 °C = (273.15 + 20) K = 293.15 K

Mass of gas(m) = 1.13 grams

ideal gas equation can be modified,

PV = (m/M) × RT, R= ideal gas constant = 0.0805 L atm/ mol K

Plug in the given data, and solve for M,

M= 32.0 g/mole

Identity of the gas is- Oxygen

2nd image solution-

Total moles= (21/14) + ( 106.5/71) + (12/4) = 6 moles

T= 14°C

V= 50 L

P= nRT/V = (6×0.08205×287.15)/50 = 2.827 atm

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