Question

Q9(a). Calculate and draw the below. [10] (b) Calculate and draw cuit for the circuit shown aw the Thevenin equi nd draw the Norton equiva wvalent for the same circuit. [10] РА R, - 30 M R2 = 20 ohm R = S

Answer 1

R = 3/2 a) The Fiven circuit is 122=623 PL = 20 Ohm V:36V The Thevenin equivalent circuit is Ran where in = The venin voltage Ron - Thevenin Resistance R = load resistance To find Thevenin voltagelven): To find divide rule ind th, open the load resistance and apply voltage 32 the 36x6 3+6 360 E 62&vih uth - 56x6 Uth = 24u To find Rthi To find Rth. Open the load resistance and short the voltage Sourites, Open the inde pendent Current sources.

31 So and 6 are in parallel Rth = Rickr tur LOA - Gri Rth RITR2 gob 3x6 3+6 5 . = 2n ... Rth=an The eat. The vinen fauivalent circuit is Rth=an Vh=24V { R=200 e The Norton equivalent circuit is Isc = Short Circuit Current (05) Norton current z RN RN = Norton resistance RL = Load resistance To find Isei To find Ise short the load resistance (kirchoff's Current Law and apply the Kch

mw->A 36V Grov Due to short Cocuit of Tood resistance there is no voltage drop anosthe on resistance. Isc tut (ov) Von - Ov => Ien - 0 Amp KCl at nede A - I + 0 + Isc = 0 - Isc = I . 360 = 12 Amp Isc = 12 Amp To calculate RN: 10 Colculate Rn Open the luad resistence, Short the independent Loltage sources, open the independent Current sources. Both zu and Gr cire in parallel umoA - Gr} RN RN = 3 v dob - 18.20 JOB Rr=en The Norton equivalent circuit is SOA Ise=1210 } RL =ron