Question

3) Calculate and draw the Norton equivalent for the circuit below, considering the load R. (15 points) 10 2v 20 w V. 2V0 w 20

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Answer #1

Given that MA + + GU R2 To find uth shoopen Re so circuit 18- 2V I-2vot I I I + With iby 80 by Kv - G = I - or 7=6 ICVL- th-avo (2+1)-2-620 vth Gvo-8=0 Tuth = 8tovo by ohms low- vo-zvo(2+10 - 20 vo- govo=2 or n1= 7 (-02I) so = -1.42 so R th= = -1.42 SD & IN= Vth 5.6 Rth -14 so IZN=nua so circuit is- IN=-UA 9 } Rth & Re

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