Mini-Prj 2. Extraction of Thevenin and Norton Equivalent Circuits by LTspice Part B. Wheatstone B...
Mini-Prj 2. Extraction of Thevenin and Norton Equivalent Circuits by LTspice Part A. Wheatstone Bridge Circuit with a Voltage Source Vs R5 R1 R2 Vs RL R3 R4 For the circuit as shown below, given that R1= 9 Ω, R2= 17 Ω, R3= 9 Ω' R,-18 Ω, R5= 19 Ω , RL= 2 Ω ,V,-74 V I. Wheatstone Bridge Circuit Analysis (a) Determining the load voltage Vi-Vab for the Wheatstone bridge circuit with LTspice Submit Answer Tries 0/3 (b) Determining...
Mini-Prj 2. Extraction of Thevenin and Norton Equivalent Circuits by LTspice Part A. Wheatstone Bridge Circuit with a Voltage Source Vs R5 R1 R2 Vs RL R3 R4 For the circuit as shown below, given that R1= 9 Ω, R2= 17 Ω, R3= 9 Ω' R,-18 Ω, R5= 19 Ω , RL= 2 Ω ,V,-74 V I. Wheatstone Bridge Circuit Analysis (a) Determining the load voltage Vi-Vab for the Wheatstone bridge circuit with LTspice Submit Answer Tries 0/3 (b) Determining...
Part B. Wheatstone Bridge Circuit with a Current Source Is R5 R1 R2 Is RL R3 R4 For the circuit as shown below, given that R1-20 Ω,R2= 12 Ω, R3-18 Ω, R4= 20 Ω, R5= 9 Ω , R.-3 ΩΊ,-15 A. I. Wheatstone Bridge Circuit Analysis (a) Determining the load voltage VL-Vab for the Wheatstone bridge circuit with LTspice. Subrnit Answer Tries 0/3 (b) Determining the load current I following from a to b for the Wheatstone bridge circuit with...
Part A. Wheatstone Bridge Circuit with a Voltage Source Vs R5 R1 R2 Vs RL R3 R4 For the circuit as shown below, given that R1: 23 Ω, R2° 13 O, R,-230, R4% 3 Ω. RS: 28 Ω , RL: 13 Ω ,Vs-90 . I. Wheatstone Bridge Circuit Analysis (a) Determining the load voltage VL-Vab for the Wheatstone bridge circuit with LTspice 1 Submit Answer Tries 0/3 (b) Determining the load current I following from a to b for the...
V1 = 20 V2 = 25 EXPERIMENT NO. 6 Thevenin & Norton Theorem Introduction Any linear network having a number of voltage, current sources and resistors can be replaced by a simple equivalent circuit consisting of a single voltage source in series with a resistance, where the value of the voltage source is equalto the open circuit voltage and the resistance is the equivalent resistance measuredbetweenthe open circuit terminals with all independent deactivated Objective To verify Thevenin's and Norton's theoremusing...
Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R = 12 Ω. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R = 12 n. Please report your answer so the magnitude is positive and all angles are in the range...
Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R =10 ohms. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R = 10 . Please report your answer so the magnitude is positive and all angles are in the range of...
Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R = 13 12. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. j42 R mo юа -j2 Ω 2/0° A -ob Zn = = Zth IN = 1) D A 1) v Vth =
A. Calculate Vout for both circuits by hand and include your calculations in your Pre-Lab B. Build the circuits in LTSpice and attach a 10K ohm termination resistor across Vout for both the Thevenin and Norton Source circuits and simulate to find the output voltages. C. What is the formula for Vout as a function of Vsource, Isource, Rload, Rs? D. Calculate Vout by hand when there is no load resistance (Rload = infinity) and again with Rload = 5K....
Find the Thevenin and Norton equivalent circuit at terminals a-b for the circuit shown below, where R = 10 . Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 1422 R -j2 22 2/0° A ob 1) ZN = Zth = IN Vth A 1) v