Question

V1 = 20 V2 = 25

EXPERIMENT NO. 6 Thevenin & Norton Theorem Introduction Any linear network having a number of voltage, current sources and resistors can be replaced by a simple equivalent circuit consisting of a single voltage source in series with a resistance, where the value of the voltage source is equalto the open circuit voltage and the resistance is the equivalent resistance measuredbetweenthe open circuit terminals with all independent deactivated Objective To verify Thevenin's and Norton's theoremusing Circuit Wizard Workbench. 5. Connect a multimeter in the resistance measuremert mode (ohnmeter) between A and B. Run the simulation and record the value of the resistor. This is RTH in Figure 1. 6. In the circuit of Figure 1 connect a variable resistor (RL)between A and B. 7. Measure the loadcurrent 8. Draw the Thevenin's equivalent circuit 9. Vary RL between 2.5 KQ to 10.5K in steps of 1 KO. Measure the load power (PL) in each case. Enter your results in Table 2. 10. Plot PL vs RL 11. Measure the current Isc/IN through AB by short-circuiting the resistance between A and B 12. Draw the Norton's equivalent circuit Table 1: Simulation and theory results for Theverin voltage and Norton current Thevenin results RTH Norton results RN VTH IL IN A IL Theory Workbench 10kΩ 1kΩ 33ko Error Vi RL Table 2: Simulation results for maximum power transfer 47k92 V2 2.5 3.5 4.5 5.5 6.5 7.5 8.5 9.5 10. RL (k 2) PL B Figure 1: DC circuit with two sources THEVENIN'S EQUIVALENT CIRCUIT NORTON'S EQUIVALENT CIRCUIT Pre-Lab Assignment: For the circuit shown Figure 1: 1- Find the Thevenin's equivalent circuit between A and B (1.e. as seen by RL) 2- Find the Norton's equivalent circuit as seen by RL. 3- Vary RL from 2.5 Kto 10.5 Kin steps of 1 K Ohms. Calculate VL in each case. For (this purpose, use the Thevenin's equivalent circuit you obtained). 4- Calculate the power PL absorbed by RL in each case of steps 3. 5- Find the value of RL for maximum power transfer andthe value of the maximumpower. 6-Summarize your results in Tables 1 and 2. Question: Procedure 1. Construct the circuit shown in Figure 1 using Circuit Wicard Workbench. 2. Remove the loadresistor R1 and connect a multimeter (orvoltmeter) to read the open circuit voltage between A and B. Simulate and record the voltage. This is VTH for this circuit between A and B. 3. Remove the V1 source. Replace it by a short circuit. Remove the V2 source. Replace it by a short circuit. 1. At what value of Ri the maximum value of PL occurs in the graph? 2. Does this value of RL compare with RTH you obtained theory or through Workbench? 4

Answer 1

Ans for Rsh, loke m 1KL 33K 12 Ron= 1011 (2+ 471133) ke Ria uke Roh= 101120.3875 Rsh= 6.71KL for Voh, loke ΙΚΩ 33K. w 47K 825V a ov 20- (0+141, + 47 ( 7, +12) 581, +47I2 20- 25 = 3312 +4712 + 4711 255 801, +471 By eq" 08 0 I, = 0.175 MA 12 = 0.209 mA - Voh at 104,-20=0 Vsh = 20-1080.175 Vyh - 18.25 V Thevenin equivalent circuits) 6.71KR MA Roh 18-25VC B

(1) 2.719 MA IN= Von Ron 12.25 6.71 Norton Equivalent, A 1719 67162 "B (ii)&(iv) VLS х 18.25 RL Retron RL * 18.25 RL+6.71 220 V? P RL 2.5kr 4.953V 9.812 mW 11.182 mW 3.5 k 2 6.2567 11.926 mW 4.5 KL. 7.326 V 12.288 mW 5.5 K2 2.221 V o. 12.403mW 6.5k2 8.9797 12.370mw 7.5kr 9.632V 8.5kh 10.1987 12.235 mW 9,5 Ke 10.695 v 12.04 mW 11.806mw 10.5ka (0) 11.134V for maximum powertoornisfer Re =Rsh R=6.71K
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