Question 16 Use the Laplace transform to solve the initial-value problem [y, +5y, = 2 cos(...
17. Use the Laplace transform to solve the initial value problem: y" + 4y' + 4y = 2e-, y(0) = 1, (O) = 3. 18. Use the Laplace transform to solve the initial value problem: 4y" – 4y + 5y = 4 sin(t) – 4 cos(1), y(0) = 0, y(0) = 11/17.
None of the above. Question 13 Use the Laplace transform to solve the initial-value problem: [y' + 2y -4 cos(5x), y(0)=2] 2) © plz) - cort5x) + 2 sin(52) + 5.24 1) 242 00452) + o) © Plz)= cos(x) + 2* sin(5x) – 60 6:20 d) y(x) =4 cos(5x) + 2 e) y(x) -4 cos(5x) - 2e2* 1) None of the above. Question 14
Use the Laplace transform to solve the given initial-value problem. y" + 6y' + 5y = 0, y(0) = 1, y'(O) = 0 y(t) =
Solve for Y(s), the Laplace transform of the solution y(t) to the initial value problem below. y' + 5y = 5t? -9, y(0) = 0, y'(0) = -3 Click here to view the table of Laplace transforms. Click here to view the table of properties of Laplace transforms. 169=122 3.sin (1960) - cos (15) -
Solve the following initial value problem using the Laplace Transform: y" + 9y = 6 cos(3x) with y(0) = -1 and y'(0) = 1
Use the Laplace transform to solve the given initial-value problem. Use the table of Laplace transforms in Appendix III as needed. y" + 25y = f(t), y(0) = 0, y (O) = 1, where RE) = {cos(5€), Ostan (Σπ rce) = f sin(51) + (t-1) -sin 5(t-T) 5 Jault- TE ) X
13. Use the Laplace transform to solve the initial value problem: (&pts) y" - 6y' + 5y = 3e, y(0) = 2, 7(0) = 3
1. (5 points) Use a Laplace transform to solve the initial value problem: y' + 2y + y = 21 +3, y(0) = 1,5 (0) = 0. 2. (5 points) Use a Laplace transform to solve the initial value problem: y + y = f(t), y(0) = 1, here f(0) = 2 sin(t) if 0 Str and f(0) = 0 otherwise.
Use the Laplace transform to solve the following initial value problem. y" - y = 32 cos(t) y(0) = 0, y'O) = 0 y(t) = 8e + + 8e – 16 cos(t)
Tutorial Exercise Use the Laplace transform to solve the given initial-value problem. y' + 5y = et (0) = 2 Step 1 To use the Laplace transform to solve the given initial value problem, we first take the transform of each member of the differential equation + 6y et The strategy is that the new equation can be solved for ty) algebraically. Once solved, transforming back to an equation for gives the solution we need to the original differential equation....