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4. When a 420 nF capacitor is connected to a voltage supply, the energy stored in...
When an air capacitor with a capacitance of 380 nF (1 nF = 10−9F) is connected...
When an air capacitor with a capacitance of 380 nF (1 nF = 10−9F) is connected to a power supply, the energy stored in the capacitor is 2.05×10−5 J . While the capacitor is kept connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 2.36×10−5 J . What is the potential difference between the capacitor plates? What is the dielectric constant of the slab?
Constants Part A When an air capacitor with a capacitance of 330 nF (1 nF 109...
Constants Part A When an air capacitor with a capacitance of 330 nF (1 nF 109 F) is connected to a power supply, the energy stored in the capacitor is 1.75x10-5J. While the capacitor is kept connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 2.72x 10-5 J What is the potential difference between the capacitor plates? V-10.3 V Previous Answers Correct Part B...
200 Fair capacitor is connected to a power supply, the energy stored in the capacitor is...
200 Fair capacitor is connected to a power supply, the energy stored in the capacitor is 900 x 10% ]. While the capacitor is kept connected to the power supply, a slab of dielectric is inserted that completely fills the space bere the plates. This increases the stored energy by 180 x 10-5 J. What is the potential difference between the capacitor plates after the dielectrie is inserted?
wirwises 2. 6 7 8 9 10 A 200 nF air capacitor in connected to a...
wirwises 2. 6 7 8 9 10 A 200 nF air capacitor in connected to a power supply, the energy stored in the capacitor is 900 x 10 J. While the capacitor is lept connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 180 x 10- J. What is the dielectric constant of the slab? 1.2 1.4 1.5 1.3 1.6 Mark This Question
. A parallel-plate capacitor of capacitance 100 HF is connected to a power supply of 200...
. A parallel-plate capacitor of capacitance 100 HF is connected to a power supply of 200 V. A dielectric slab of dielectric constant 5 is now inserted into the gap between the plates. (a) Find the extra charge flown through the power supply and the work done by the supply. (b) Find the change in the electrostatic energy of the electric field in the capacitor.
Part A and Part B please Part A Constants What is the potential difference between the...
Part A and Part B please
Part A Constants What is the potential difference between the capacitor plates? When an air capacitor with a capacitance of 350 nF (1 nF 10 F is connected to a power supply, the energy stored in the capacitor is 2.05x10-s J. While the capacitor is kept connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 2.48x105 J. You...
A 12.5μF capacitor is connected to a power supply that keeps a constant potential difference of...
A 12.5μF capacitor is connected to a power supply that keeps a constant potential difference of 24.0 V across the plates. A piece of material having a dielectric constant of 3.75 is placed between the plates, completely filling the space between them. a.) How much energy is stored in the capacitor before the dielectric is inserted? b.) How much energy is stored in the capacitor after the dielectric is inserted? c.) By how much did the energy change during the...
A parallel-plate vacuum capacitor is connected to a batteryand charged until the stored electric energy is...
A parallel-plate vacuum capacitor is connected to a battery and charged until the stored electric energy is U. The
battery is removed, and then a dielectric material with dielectric
constant K is inserted
into the capacitor, filling the space between the plates. Finally,
the capacitor is fully discharged through a resistor (which is
connected across the capacitor terminals).A.)Find Ur, the
the energy dissipated in the resistor.Express your answer in terms
of U and other
given quantities.B.) Consider the same situation...
A parallel-plate capacitor of capacitance Co, plate area A, spacing d is charged to voltage V....
A parallel-plate capacitor of capacitance Co, plate area A, spacing d is charged to voltage V. and then disconnected from the charging battery. A slab with dielectric constant K and thickness d/2 is thrust into the capacitor, as shown in the figure below; the slab is exactly halfway between the plates. к (a) What is the new capacitance in terms of Co? (b) What is the ratio of the stored energy before to that after the slab is inserted (U/0.)?...
A 2.0 μF parallel-plate air-filled capacitor is connected across a 10 V battery. (a) Determine the...
A 2.0 μF parallel-plate air-filled capacitor is connected across a 10 V battery. (a) Determine the charge on the capacitor and the energy stored in the capacitor. (b) An identical 2.0 μF parallel-plate air-filled capacitor is connected across a 5 V battery, and a dielectric slab with dielectric constant κ is inserted between the plates of the capacitor, completely filling the region between the plates, while the battery remains connected. The energy stored in this capacitor is four times that...
Constants Part A When an air capacitor with a capacitance of 330 nF (1 nF 109 F) is connected to a power supply, the energy stored in the capacitor is 1.75x10-5J. While the capacitor is kept connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 2.72x 10-5 J What is the potential difference between the capacitor plates? V-10.3 V Previous Answers Correct Part B...
200 Fair capacitor is connected to a power supply, the energy stored in the capacitor is 900 x 10% ]. While the capacitor is kept connected to the power supply, a slab of dielectric is inserted that completely fills the space bere the plates. This increases the stored energy by 180 x 10-5 J. What is the potential difference between the capacitor plates after the dielectrie is inserted?
wirwises 2. 6 7 8 9 10 A 200 nF air capacitor in connected to a power supply, the energy stored in the capacitor is 900 x 10 J. While the capacitor is lept connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 180 x 10- J. What is the dielectric constant of the slab? 1.2 1.4 1.5 1.3 1.6 Mark This Question
. A parallel-plate capacitor of capacitance 100 HF is connected to a power supply of 200 V. A dielectric slab of dielectric constant 5 is now inserted into the gap between the plates. (a) Find the extra charge flown through the power supply and the work done by the supply. (b) Find the change in the electrostatic energy of the electric field in the capacitor.
Part A and Part B please
Part A Constants What is the potential difference between the capacitor plates? When an air capacitor with a capacitance of 350 nF (1 nF 10 F is connected to a power supply, the energy stored in the capacitor is 2.05x10-s J. While the capacitor is kept connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 2.48x105 J. You...
A parallel-plate vacuum capacitor is connected to a battery and charged until the stored electric energy is U. The
battery is removed, and then a dielectric material with dielectric
constant K is inserted
into the capacitor, filling the space between the plates. Finally,
the capacitor is fully discharged through a resistor (which is
connected across the capacitor terminals).A.)Find Ur, the
the energy dissipated in the resistor.Express your answer in terms
of U and other
given quantities.B.) Consider the same situation...
A parallel-plate capacitor of capacitance Co, plate area A, spacing d is charged to voltage V. and then disconnected from the charging battery. A slab with dielectric constant K and thickness d/2 is thrust into the capacitor, as shown in the figure below; the slab is exactly halfway between the plates. к (a) What is the new capacitance in terms of Co? (b) What is the ratio of the stored energy before to that after the slab is inserted (U/0.)?...
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