(A) U = C V^2 /2
(1.75 x 10^-5) = (330 x 10^-9) V^2 / 2
V = 10.3 Volt
(B) C' = k C
As it is connected to battery, PD will remain same
V= 10.3 Volt
U = C' V^2 / 2
((1.75 x 10^-5) + (2.72 x 10^-5)) = (k x 330 x 10^-9) (10.3^2) /2
k = 2.55
Constants Part A When an air capacitor with a capacitance of 330 nF (1 nF 109...
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