Calculate the energy stored in 0.632 mH inductor with a current of 30.0 A.
Magnetic energy stored in an inductor is U= (1/2)*L*I2
Where L is inductance of the inductor = 0.632 mH = 0.632×10-3 H.
And I is the current through the inductor = 30 A.
Energy stored U = (1/2)*(0.632×10-3)*(30)2 joule = 0.2844 joule.(ans)
Calculate the energy stored in 0.632 mH inductor with a current of 30.0 A.
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