Question

23. a) mAB = 80°, m ZAEB = 75°, mCD = ? b) mAC 62°, m ZDEB = 45°, mBD = ? c) mAB 88°, mZP = 24°, mZCED = ? d) mZCED = 41°, mCD = 20°, mZP = ? e) m ZAEB 65°, mZP = 25°, m AB 25°, mAB = ?, mCD = ? f) mZ CED 50°, MAC + mBD = ? P C A E D В

Need help with 'e' and 'f'

Answer 1

% P A E Given that mL AEB = 650 MLP = 25° Angle formed by two chords = {(su q intercepted Ancs) M_ACB=(map + m@B 1 Cm AB tm CD) 3) MAB + m2 65°x2 = 130* Angle formed by two secart 1 (Difference of Intercepted Ares) m 2q = ļ (MAB-MED) (MAB - MCD) => 6505 e 7 25°= mAB - m CD = 250x2=5 50° M Add equation 0 20 MAB +m ma on AB MED= so 1309 2 MAB = 180° MAB - 190= 90'] (Anester MAB + m CD = 130* 90 + MCD- MCD = 130 mco - 130- 90°- 140] (Answer € Given that M L CED - 50" MLCEDA (MAB + CD) → MÁB + mCD = 50x2=100 MAB + MBD + m CD + MAC = 360 (maB + BD+mAC)= 360 a) C + m Bộ : 360 - (Ag + mệp)= 360 - Joo - 20 tm mco) +(MBD -) (Answer)