13. Which compound shown below would NOT be a product from the reaction of m-chlorotoluene with...
13. In step 5 of reaction 3, the reaction mixture containing the products shown below in ethyl acetate is extracted twice with HCI. NH2 NH2 HN o-methylaniline m-methylaniline p-methylacetanilide a) Which products (shown above) from reaction 3 can react with HCl in an acid-base reaction? Show the mechanism for this acid-base reaction and give the structures that would result from the protonation of these products. Which phase (organic or aqueous) would these protonated products be soluble in? (6 points) b)...
13. In step 5 of reaction 3, the reaction mixture containing the products shown below in ethyl acetate is extracted twice with HCI. NH2 NH HN o-methylaniline m-methylaniline p-methylacetanilide a) Which products (shown above) from reaction 3 can react with HCl in an acid-base reaction? Show the mechanism for this acid-base reaction and give the structures that would result from the protonation of these products. Which phase (organic or aqueous) would these protonated products be soluble in? (6 points) b)...
Which of the reactions will yield the indicated compound as the
major product? Check all that apply.
CI (i) CI ♡ CI 1. HNO3, H2SO4 2. HN(CH3)2 NO2 CI (ii) 1. HNO3, H2SO4 2. HN(CH3)2 NO2 CI CI (iii) OCH3 OCH3 1. HNO3, H2SO4 2. HN(CH3)2 O2N CI (iv) OCH3 1. NaN(CH3)2, HN(CH3)2 OCHZ 2. Br2 Br H2C H2C CI (v) H3C AICI: H3C CH3 CH3 (vi) H2N 1) HNO3, H2SO4 HN 2) NaOH, H2O NO2
13. In step 5 of reaction 3, the reaction mixture containing the products shown below in ethyl acetate is extracted twice with HCI. NH2 NH HN o-methylaniline m-methylaniline p-methylacetanilide a) Which products (shown above) from reaction 3 can react with HCl in an acid-base reaction? Show the mechanism for this acid-base reaction and give the structures that would result from the protonation of these products. Which phase (organic or aqueous) would these protonated products be soluble in? (6 points) Reaction...
a) Which products (shown above) from reaction 3 can react with
HCl in an acid-base reaction? Show the mechanism for this acid-base
reaction and give the structures that would result from the
protonation of these products. Which phase (organic or aqueous)
would these protonated products be soluble in?
b) Which phase (organic or aqueous) would the
p-methylacetanilide be found in?
In step 5 of reaction 3, the reaction mixture containing the products shown below in ethyl acetate is extracted twice...
69
doesnt have a picture of any reaction for some reason
QUESTION 68 What is the word that can be used to relate the following polymers? Ph Ph Ph Ph Diastereomers They are the same Constitutional isomers Enantiomers QUESTION 69 What would be true about the product of the following reaction? an achiral cyclopropane would result an achiral di-iodide would result an chiral cyclopropane would result an achiral alkyne would result QUESTION 70 How many additional resonance structures can be...
a) Which products (shown above) from reaction 3 can react with
HCl in an acid-base reaction? Show the mechanism for this acid-base
reaction and give the structures that would result from the
protonation of these products. Which phase (organic or aqueous)
would these protonated products be soluble in?
b) Which phase (organic or aqueous) would the
p-methylacetanilide be found in?
c) Why did we have to use hot ethanol for the
recrystallization?
d) Why did we have to cool the...
47. Draw the product formed from the following reaction. (3 marks) CH3 Heat H2 H2 H3C + OH HN -C—CH3 48. Identify the compounds in the following pair as structural isomers, same compound or different compounds. (2 marks) and
12. Which is the major product of the reaction shown? (a) (b)
(c) (d) 13. What are all of the possible products formed in the
following reaction? (choose all correct answers) (a) (b) (c) (d)
(e) (f) 14. The three compounds below can form a carbocation in the
presence of H2O and H2SO4. Which ones will form the same
carbocation? (a) I and II (b) I and III (c) II and III (d) all
three will form the same carbocation...
11. Which of the following best explains why the synthetic route shown below would be unsuccessful? 2) NaNH2 3) (CHs)hCBr A) The alkynide anion is not a strong enough nucleophile to react with 1-bromopropane in step 1 m amide is not a strong enough base to deprotonate the terminal alkyne in step anion formed by reaction with sodium amide will facilitate an E2 (rather C) The alkynide than SN2) reaction with t-butyl bromide. 5oth substtution reactions will occur on the...