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Image for A section of superconducting wire carries a Current of loo A and requires 100 L of liquid nitrogen per hour to


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Answer #1

here ,

cost of cooling using liquid nitrogen , C = cost of liquid N2 per litre * volume

C = 0.30 $ * 1

C = 0.30 $ per hour

Now, energy used for 0.30 $

energy = 0.30/0.10

energy = 3 kW.h

now,the power in the wire can be 3 kW

let the resistance is R ,

Power = i^2 * R

3000 = 100^2 * R

R = 0.3 ohm

the resistance of wire can be 0.3 Ohm

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