Question

7. A force causes a mass of 4 kg to have an acceleration of 8 m/s2. Suppose something causes the (1 point) mass to be one-quarter of its original amount. What will happen to the acceleration if the amount of force used remains the same? It will decrease to 2 m/s2 It will remain the same. It will increase to 32 m/s2. It will increase to 16 m/s2 8. What is the force required to propel a 2.00 kg object at a rate of 2.71 x 10 m/s2? (1 point) 5.42 x 105 N 5.44 105 N 5.40 x 105N 5.38 x 105N 9. What is the acceleration of the 698 kg car that experiences a force of 2410 N? (1 point) 0.290 m/s2

Answer 1

Question 7

intial mass = 4 kg

initial acceleration = 8 m/s²

initial force = m * a = 4 * 8 = 32 N

now current mass = (1/4 ) of the original mass

= ( 1/4 ) * 4

final mass = 1 kg

final force = initial force = 32 N

so final accelration = Final force / final mass

final acceleration = 32 / 1

final acceleration = 32 m/s² <<<<<< Option C

Question 8

mass = 2.00 kg

accelration = 2.71 x 10⁵ m/s²

Force = m * a

= 2.00 * 2.71   x 10⁵

= 5.42 x 10⁵ N <<<<<< option 1