Question

Please answer questions 1 and 2

on The rate constant for the reaction answered A + B->C out of 1.0 is 4.1 x104 U(mol s) at 593 K. The activation energy is 101 kj/mol. question Determine the temperature when the rate constant is 1.2 x10-3 L/(mol s)- Answer: 2 One (often inaccurate) rule of thumb in biology is that a 10 °C change increases the rate by a factor of ten. If the lower temperature is 3 °C, what activation energy does this correspond? Report your answer in kj/mol. on et answered ed out of 1.0 g question Answer tion 3 The reaction rate for a chemical reaction was measured as a function of temperature. Determine the activation energy for the reaction. Report your answer in k/mol answered ked out of 1.0 Temp/K Rate constant /arb.

Answer 1

According to arrhenius equation

K = K_oe^-E_A/RT

K = rate constant

T = temperature

E_A = activation energy

for 2 different temperature ,the equation can be rearranged as:

ln(K₂/K₁) = E_A/R[1/T₁ - 1/T₂]

ln{1.2 x 10^-3/4.1 x 10^-4 } = 10100J/mol / 8.314J/mol.K[1/593K - 1/T₂]

T₂ = 1246.48 K

b)

3^oC = 273 + 3 = 276K

10 ^oC increment = 276 + 10 = 286K

ln(r₂/r₁) = E_A/8.314J/mol.K[1/276K - 1/286K] given r₂ = 10 r₁

ln10 x 8.314 /[1/276K - 1/286K] = E_A

151112.65 J/mol = 151.113 kJ/mol = E_A