Question

Identify the integral used to determine the surface area of the surface of revolution for the shape described Byy=3 sin() +3,
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Answer #1

y= 3 sin ( 3 ) +3 os x< Axis of rewa, ae dy AY dl= √ (dx)² = (dy)? = √( dy dj 1 ax Sweface of revolwan for de about yaxs ds=inde 2ay.de = 27.3[1+ sin(73] dy = 3.60Hope explanation is fine.

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